Optimal. Leaf size=53 \[ \frac{3 a^2 (a+b x)^{5/3}}{5 b^3}+\frac{3 (a+b x)^{11/3}}{11 b^3}-\frac{3 a (a+b x)^{8/3}}{4 b^3} \]
[Out]
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Rubi [A] time = 0.0393378, antiderivative size = 53, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.077 \[ \frac{3 a^2 (a+b x)^{5/3}}{5 b^3}+\frac{3 (a+b x)^{11/3}}{11 b^3}-\frac{3 a (a+b x)^{8/3}}{4 b^3} \]
Antiderivative was successfully verified.
[In] Int[x^2*(a + b*x)^(2/3),x]
[Out]
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Rubi in Sympy [A] time = 7.93304, size = 49, normalized size = 0.92 \[ \frac{3 a^{2} \left (a + b x\right )^{\frac{5}{3}}}{5 b^{3}} - \frac{3 a \left (a + b x\right )^{\frac{8}{3}}}{4 b^{3}} + \frac{3 \left (a + b x\right )^{\frac{11}{3}}}{11 b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**2*(b*x+a)**(2/3),x)
[Out]
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Mathematica [A] time = 0.0175047, size = 46, normalized size = 0.87 \[ \frac{3 (a+b x)^{2/3} \left (9 a^3-6 a^2 b x+5 a b^2 x^2+20 b^3 x^3\right )}{220 b^3} \]
Antiderivative was successfully verified.
[In] Integrate[x^2*(a + b*x)^(2/3),x]
[Out]
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Maple [A] time = 0.007, size = 32, normalized size = 0.6 \[{\frac{60\,{b}^{2}{x}^{2}-45\,abx+27\,{a}^{2}}{220\,{b}^{3}} \left ( bx+a \right ) ^{{\frac{5}{3}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^2*(b*x+a)^(2/3),x)
[Out]
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Maxima [A] time = 1.34847, size = 55, normalized size = 1.04 \[ \frac{3 \,{\left (b x + a\right )}^{\frac{11}{3}}}{11 \, b^{3}} - \frac{3 \,{\left (b x + a\right )}^{\frac{8}{3}} a}{4 \, b^{3}} + \frac{3 \,{\left (b x + a\right )}^{\frac{5}{3}} a^{2}}{5 \, b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)^(2/3)*x^2,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.207486, size = 57, normalized size = 1.08 \[ \frac{3 \,{\left (20 \, b^{3} x^{3} + 5 \, a b^{2} x^{2} - 6 \, a^{2} b x + 9 \, a^{3}\right )}{\left (b x + a\right )}^{\frac{2}{3}}}{220 \, b^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)^(2/3)*x^2,x, algorithm="fricas")
[Out]
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Sympy [A] time = 5.92255, size = 666, normalized size = 12.57 \[ \frac{27 a^{\frac{35}{3}} \left (1 + \frac{b x}{a}\right )^{\frac{2}{3}}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} - \frac{27 a^{\frac{35}{3}}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} + \frac{63 a^{\frac{32}{3}} b x \left (1 + \frac{b x}{a}\right )^{\frac{2}{3}}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} - \frac{81 a^{\frac{32}{3}} b x}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} + \frac{42 a^{\frac{29}{3}} b^{2} x^{2} \left (1 + \frac{b x}{a}\right )^{\frac{2}{3}}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} - \frac{81 a^{\frac{29}{3}} b^{2} x^{2}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} + \frac{78 a^{\frac{26}{3}} b^{3} x^{3} \left (1 + \frac{b x}{a}\right )^{\frac{2}{3}}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} - \frac{27 a^{\frac{26}{3}} b^{3} x^{3}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} + \frac{207 a^{\frac{23}{3}} b^{4} x^{4} \left (1 + \frac{b x}{a}\right )^{\frac{2}{3}}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} + \frac{195 a^{\frac{20}{3}} b^{5} x^{5} \left (1 + \frac{b x}{a}\right )^{\frac{2}{3}}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} + \frac{60 a^{\frac{17}{3}} b^{6} x^{6} \left (1 + \frac{b x}{a}\right )^{\frac{2}{3}}}{220 a^{8} b^{3} + 660 a^{7} b^{4} x + 660 a^{6} b^{5} x^{2} + 220 a^{5} b^{6} x^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**2*(b*x+a)**(2/3),x)
[Out]
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GIAC/XCAS [A] time = 0.223572, size = 62, normalized size = 1.17 \[ \frac{3 \,{\left (20 \,{\left (b x + a\right )}^{\frac{11}{3}} b^{20} - 55 \,{\left (b x + a\right )}^{\frac{8}{3}} a b^{20} + 44 \,{\left (b x + a\right )}^{\frac{5}{3}} a^{2} b^{20}\right )}}{220 \, b^{23}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x + a)^(2/3)*x^2,x, algorithm="giac")
[Out]